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Determine the structure for C6H13Cl using the following data.
The H NMR for C6H13Cl states that there are 3 different types of protons:
6H, triplet
4H, quartet
3H, singlet
What will the structure look like?
The molecule you're looking at is 3chloro3methylpentane.
Symmetry causes H NMR to integrate 2x for the 6H and 4H signals.
Here's a useful hint: when you have a triplet and a quartet with the area ratio given as above, it indicates the presence of ethyl groups. Since the total area under those peaks is 10 H, there are two of these groups equivalent to each other. Only one isomer with the given formula does that.

The molecule you're looking at is 3chloro3methylpentane.
Symmetry causes H NMR to integrate 2x for the 6H and 4H signals.
20180410 05:05:01 
Here's a useful hint: when you have a triplet and a quartet with the area ratio given as above, it indicates the presence of ethyl groups. Since the total area under those peaks is 10 H, there are two of these groups equivalent to each other. Only one isomer with the given formula does that.
20180410 05:31:19