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Why is the normal force a hypotenuse of the weight force? Isn't it a component of the weight force?

2018-06-05 08:20:11

I thought the answer would be the horizontal component of the net force acting down the slope, but apparently not. Please explain why this is right or if this is right.

P.S. I know there is a similar question asked here but it relates to the mass of the plane, which is not given here.

Try setting up a coordinate system along the hypotenuse and perpendicular to it. Then resolve the forces in those two axes. Finally equate the forces along the hypotenuse to achieve equilibrium. You will get your answer after that.

The normal reaction is perpendicular to the plane.

Resolve the normal reaction into a horizontal component and a vertical component, equate horizontal and vertical forces and use the resulting equations to eliminate the normal reaction.

• Try setting up a coordinate system along the hypotenuse and perpendicular to it. Then resolve the forces in those two axes. Finally equate the forces along the hypotenuse to achieve equilibrium. You will get your answer after that.

2018-06-05 08:24:31
• The normal reaction is perpendicular to the plane.

Resolve the normal reaction into a horizontal component and a vertical component, equate horizontal and vertical forces and use the resulting equations to eliminate the normal reaction.

2018-06-05 09:32:27